**Molarity of 95% (w/w) Sulfuric acid (H2SO4)**

**Overview:**

- Sulfuric acid (H2SO4) is a clear colourless liquid. A 95% (w/w) concentrated Sulfuric acid can be obtained from different suppliers.
- 95% (w/w) Sulfuric acid means that 100 grams of Sulfuric acid contains 95 grams of H2SO4.
- The density of 95% (w/w) Sulfuric acid is 1.84 g/ml at 25°C that means that weight of the 1 ml of Sulfuric acid is 1.84 gram at 25°C.
- Molarity refers to number of moles of the solute present in 1 litre of solution.
- In simple words, 1 mole is equal to atomic weight of the substance. For example, 1 mole of H2SO4 is equal to 98.08 grams of H2SO4 (molecular weight = 98.08).

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**Calculation procedure:**

**Known values:**

Density of Sulfuric acid : 1.84 g/ml

Molecular weight of H2SO4: 98.08 g/mole

Concentration of Sulfuric acid: 95% (% by mass, wt/wt)

**Step 1: Calculate the volume of 100 grams of Sulfuric acid.**

**Formula:**

Density = weight / volume or

Volume = weight / density or

Volume of 100 gram of Sulfuric acid : 100/1.84 = 54.3478 ml

Note: 95% (w/w) Sulfuric acid means that 100 grams of Sulfuric acid contain 95 grams of H2SO4.

**The volume of 100 grams of Sulfuric acid is 54.3478 ml. That means 95 grams of H2SO4 is present in 54.3478 ml of Sulfuric acid.**

**Step 2: Calculate how many grams of H2SO4 is present in 1000 ml of Sulfuric acid.**

54.3478 ml of Sulfuric acid contain = 95 grams of H2SO4

1 ml of Sulfuric acid will contain = 95/54.3478 grams of H2SO4

1000 ml of Sulfuric acid will contain = 1000 x 95/54.3478 = 1748 grams of H2SO4

**1000 ml of Sulfuric acid will contain 1748 grams of H2SO4**

**Step 3: Calculate number of moles of H2SO4 present in **1748** grams of H2SO4.**

98.08 grams of H2SO4 is equal to 1 mole.

1 gram of H2SO4 will be equal to 1/98.08 moles.

1748 grams will be equal to = 1748 x 1/98.08 = 17.822 moles

**T****herefore, we can say that 1 litre of Sulfuric acid contains 17.822 moles or in other words molarity of 95% (w/w) Sulfuric acid is equal to 17.822 M.**