# Overview:

• Sulfuric acid (H2SO4) is a clear colourless liquid. A 95% (w/w) concentrated Sulfuric acid can be obtained from different suppliers.
• 95% (w/w) Sulfuric acid means that 100 grams of Sulfuric acid contains 95 grams of H2SO4.
• The density of 95% (w/w) Sulfuric acid is 1.84 g/ml at 25°C that means that weight of the 1 ml of Sulfuric acid is 1.84 gram at 25°C.
• Molarity refers to number of moles of the solute present in 1 litre of solution.
• In simple words, 1 mole is equal to atomic weight of the substance. For example, 1 mole of H2SO4 is equal to 98.08 grams of H2SO4 (molecular weight = 98.08).

# Calculation procedure:

Known values:
Density of Sulfuric acid :                             1.84 g/ml
Molecular weight of H2SO4:                       98.08 g/mole

Concentration of Sulfuric acid:            95% (% by mass, wt/wt)

## Step 1: Calculate the volume of 100 grams of Sulfuric acid.

Formula:
Density =  weight / volume    or

Volume =  weight / density    or

Volume of 100 gram of Sulfuric acid : 100/1.84 =  54.3478 ml

Note: 95% (w/w) Sulfuric acid means that 100 grams of Sulfuric acid contain 95 grams of H2SO4.

The volume of 100 grams of Sulfuric acid is 54.3478 ml. That means 95 grams of H2SO4 is present in 54.3478 ml of Sulfuric acid.

## Step 2: Calculate how many grams of H2SO4 is present in 1000 ml of Sulfuric acid.

54.3478 ml of Sulfuric acid contain       = 95 grams of H2SO4
1 ml of Sulfuric acid will contain           = 95/54.3478 grams of H2SO4

1000 ml of Sulfuric acid will contain     = 1000 x 95/54.3478 = 1748 grams of H2SO4

1000 ml of Sulfuric acid will contain 1748 grams of H2SO4

## Step 3: Calculate number of moles of H2SO4 present in 1748 grams of H2SO4.

98.08 grams of H2SO4 is equal to 1 mole.
1 gram of H2SO4 will be equal to 1/98.08 moles.
1748 grams will be equal to = 1748 x 1/98.08 = 17.822 moles

Therefore, we can say that 1 litre of Sulfuric acid contains 17.822 moles or in other words molarity of 95% (w/w) Sulfuric acid is equal to 17.822 M.