Calculating amount of Disodium ethylenediaminetetraacetate dihydrate (EDTA.Na2.2H2O) for preparation of 1 litre of 0.5 M EDTA solution

Calculating amount of Disodium ethylenediaminetetraacetate dihydrate (EDTA.Na2.2H2O) for preparation of 1 litre of 0.5 M EDTA solution

Molecular weight of EDTA.Na2.2H2O = 372.24 g/mol
Solution volume = 1 L
Desired molarity of solution = 0.5 M
Amount of substance (in grams) = To be calculated

Formula :

Place all values in the formula
Amount of substance (in grams) = 0.5 x 372.24 x 1
                                                          = 186.12 grams

Conclusion: To prepare 1 litre of 0.5 M solution, you need 186.12 grams of Disodium ethylenediaminetetraacetate dihydrate (EDTA.Na2.2H2O).